Two parts Someone please help Part one: Write a function rule for the area of a rectangle with a length of 2 ft less than three times its width.
Part two: what is the area of the rectangle when its width is 2 ft?

Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x

Part two: The area of the rectangle is 8 feet² when its width is 2 feet

Step-by-step explanation:

Assume that the width of the rectangle is x

∵ The width of the rectangle = x feet

∵ The length of the rectangle is 2 ft less than three times its width

→ That means multiply the width by 3, then subtract 2 from the product

∴ The length of the rectangle = 3(x) - 2

∴ The length of the rectangle = (3x - 2) feet

∵ The area of the rectangle = length × width

∴ A(x) = (3x - 2) × x

→ Multiply each term in the bracket by x

∵ A(x) = x(3x) - x(2)

∴ A(x) = 3x² - 2x

∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x

∵ The rectangle has a width of 2 ft

∵ The width = x

∴ x = 2

→ Substitute x by 2 in A(x)

∵ A(2) = 3(2)² - 2(2)

∴ A(2) = 3(4) - 4

∴ A(2) = 12 - 4

∴ A(2) = 8

∴ The area of the rectangle is 8 feet² when its width is 2 feet

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.