Given: Bis the midpoint of DC and 2D AZC Prove: ZEZA
D
E
B
STATEMENTS
1. Bis the midpoint of DC
2. DB BC
3. 2D2C
4. ABC 2 ZEBD
5. ABC AEBD
6. ZE ZA
REASONS
1. Given
2. Definition of Midpoint
3. Given
4.
5.
6.
Which of the following lists the missing reasons in the respective order?
Alternate Interior Angle Theorem, ASA, CPCTC
Vertical Anglo Thoorom, ASA, CPCTC
Linear Pair Postulate, SSS, CPCTC
Reflexive Property, CPCTC, AAS

yo answer should be 6 if im not mistaken

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.