The function P(t)=87,000e^0.106t models the population of a city, t years after 2010. How many people lived in the city in 2010? At what rate is the population change in? Explain

87,000 ; 10.6%

Step-by-step explanation:

Given the function :

P(t)=87,000e^0.106t

P(t) is an exponential function ; comparing the given function to the general form of an exponential function :

y = Ae^rt

Where,

A = initial amount ; r = growth rate ; t = time

The Given function models t years after 2010, that is the 2010 population is the initial population of the city.

Comparing the general exponential equation with the function given:

A = 87,000 = population of city in 2010

The growth rate :

rt from the general equation compares to 0.106t in the given function.

rt = 0.106t

r = 0.106

Hence, the rate of change = 0.106 * 100% = 10.6%

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .