PLS HELP any hints appericated(40 Points) A few algebra problems,
1.Solve the equation: [4ax - (a + b)](a + b) = 0, where a and b are constants.
2.Solve the equation m^2x + 1 = m(x + 1), where m is a parameter.
3.Given that the equation a(2x - 1) = 3x - 3 has no solution, find the value of the parameter a.

Step-by-step explanation:

1) Solve the equation: [4ax - (a + b)](a + b) = 0, where a and b are constants.

or

2) Solve the equation m²x + 1 = m(x + 1), where m is a parameter.

3) Given that the equation a(2x - 1) = 3x - 3 has no solution, find the value of the parameter a.

The equation has no solution if:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐