Can someone help me on the steps for this?

x = 13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Algebra I

Multiple Roots

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is a leg b is another leg c is the hypotenuse

Step-by-step explanation:

Step 1: Identify

a = 12

b = 5

c = x

Step 2: Solve for x

Substitute in variables [PT]:                                                                           12² + 5² = x²Evaluate exponents:                                                                                      144 + 25 = x²Add:                                                                                                                 169 = x²[Equality] Square root both sides:                                                                 ±13 = xRewrite:                                                                                                           x = ±13

Since we are dealing with positive numbers, we can disregard the negative root.

∴ x = 13

Funds fun jf j efj did i.e. c he'd midi code oexpwxo.pax,lexie x cucumber ice jd cud jd jf j k k j d

Oof.tijn nwcjfwj fjg2