The sum of the number is 103.the second number is 4 times the third. the third number is 5 more then the first .what are the numbers ?

13, 18, 72

Step-by-step explanation:

let x-5 represent the first number, since the first number is 5 less than the third number. let x represent the third number. let 4x represent the third number, since it's four times greater than the third number.

set up an equation, and make it equal to 103:

x-5+x+4x=103

solve:

6x-5=103

6x=108

x=18

so, the third number is 18.

the first number is equal to x-5, so:

18-5=13

the second number is equal to 4x, so:

4(18)=72

so, the three numbers are 13, 18, and 72.

the answer should be:

a. 3, 4, and 6

b. 18, 24, and 36

c. 4.8, 6.4, and 9.6

hope i

-lavira : )

same question do you know the answer