Write the equation of a line that is perpendicular to the line y = x – 5 and contains the point (-4, 13)?

y = -x + 9

Step-by-step explanation:

Here, we want to write the equation of a line

mathematically, if two lines are perpendicular, the product of their slopes is -1

Comparing the given equation with the general form of;

y = mx + b

where m is the slope and b is the y-intercept, we can see that the slope value is 1

So the slope of the second line will be;

-1/1 = -1

now we want to write the equation of a line that has a slope of -1 and passes through the point (-4, 13)

we use the point-slope form here

That will be;

y-y1 = m(x-x1)

y-13 = -1(x+ 4)

y-13 = -x - 4

y = -x -4 + 13

y = -x + 9

neither i nor ii 56 / 4.9 = 11.91489362 and 82 / (11+5) =5.125 so i is wrong

ii. (24/8+2) times 3 = 15 and (42+9)/2 =25.5

step-by-step explanation:

56

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2