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Question ID: 559448
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Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and d are
integers.
1. x2 - 6x + 8 = (ax + b)(cx + d)
2. 3x3 - 6x? - 24x = 3x(ax + b)(cx + d)
3. 2x2 - 2x - 24 = (ax + b)(cx + d)
Fill in the table with the missing values of a, b, c, and d.
b
d
a
с
1. 1
-4
1
-2
2.1
2.
3.
-4
2
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u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

sasaasasa

step-by-step explanation:

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