I’ll give the Brainliest to who answers this question with a reasonable explanation. The population of a small town increased 23% from its population in 2000 to its population in 2003. If the population of the town in 2000 was 25,314, what was its population in 2003?

31136

Step-by-step explanation:

To find the how much an number increased by a percent. Divide the percent by 100. 23/100=0.23.

Then multiply 0.23 by the original number which is 25,314. Which gives us about 5822.

Then since it INCREASED, we are going to add that number it increased to the original. 25314+5822= 31136.

Good Luck, hope it helps:)

Step-by-step explanation:

23% of 25,314 = 25,314 x .23 = 5822 then add that to the original population. 25,314 + 5,822 = 31,136

(wateroflife18,

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt