One airplane located 200km north and 50km east of an airport. A second plane at the same altitude is located 30km north and 100km west. The distance between the planes is closet to:

200

Step-by-step explanation: You can use the Pythagorean theorem for this question. First, you must find a and b. You can do this by finding the distance between North and South, and East and West. For this specific equation, you'd use 200 North - 30 North to get 170 miles on the y-axis. Then, you'd do 50 East + 100 West to get 150 kilometers distance on the x-axis. Now that you have 170 and 150, you can begin the equation

170^2 + 150^2 = c^2

28900 + 22500 = c^2

51400 = c^2

√51400 = √c^2

~226 = c

They are approximately 226 kilometers apart, and 226 is closest to 200, which is B.

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

step-by-step explanation: