Atriangle is enlarged by a factor of 3. the perimeter of the new triangle is 36 feet. what could be the lengths of the sides of the original triangle?

The possible sides of the triangle may be 3, 4, 5 feet.

Step-by-step explanation:

Let the sides of a triangle are x, y, z. If these sides are enlarged by a factor of 3 then these sides will become 3x, 3y, and 3z.

Now the perimeter of the given triangle will be

P = 3(x + y + z) = 36

So x + y + z = 12

since to form a triangle condition that should be followed is

x + y > z

Therefore by hit and trial method sides of the triangle may be 3, 4, and 5 which we can check by putting the values of the sides in the original equation.

x + y > z ⇒ 3 + 4 > 5 ⇒ 7 > 5

and 3( x + y + z) = 3(3 + 4 + 5) = 3×12 = 36

a

step-by-step explanation:

its wrong

2 equivalent expressions to represent the area of a rectangle and the top is n-3 and the side is 2

area of the rectangle = length * width

given length = n - 3

width = 2

replace it in the area

so area of the rectangle = (n-3) *2

= 2(n-3)

one of the expression is 2(n-3)

to get another expression we distribute 2 inside the parenthesis

2(n-3) is 2n - 6

so another expression is 2n - 6

two equivalent expression are

2(n - 3)   , 2n - 6