Mathematics, 27.01.2021 17:10 dayday0
A skydiver jumps from an airplane and accelerates toward the ground. His velocity can be modeled by the function v(t)=1000t5t+8, where v(t) is the velocity in feet per second, and t represents time in seconds. Due to air resistance, there is a limiting velocity the skydiver will not exceed, called the "terminal velocity". At terminal velocity, the velocity does not continue to increase. What is the terminal velocity? Justify your answer.
Answers: 2
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For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
A skydiver jumps from an airplane and accelerates toward the ground. His velocity can be modeled by...
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