Find the perimeter of AABC.
B
5x-19
2x +11
А
16
10
0 31
0 47
78

78

Step-by-step explanation:

Since the base angles are congruent, then the triangle is isosceles and

AB = BC , that is

5x - 19 = 2x + 11 ( subtract 2x from both sides )

3x - 19 = 11 ( add 19 to both sides )

3x = 30 ( divide both sides by 3 )

x = 10

Then

AB = BC = 2x + 11 = 2(10) + 11 = 20 + 11 = 31

Thus

perimeter = 31 + 31 + 16 = 78

the answer will be

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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