Gina Wilson unit 6 homework 4

10) 57.611) 27.3 12) 12.75 13) 1014) 14 15) 5

Step-by-step explanation:

If three or more parallel lines are cut by two transversals, then they divide the transversals proportionally.

Using the above we find the value of x

10.

x/48 = 30/25x/48 = 6/5x = 48*1.2x = 57.6

11.

x/ (49 - 28) = 36.4/28x/21 = 9.1/7x = 21*9.1/7x = 27.3

12.

(2x + 6)/36 = 52.5/60(x + 3)/18 = 7/8x + 3 = 18*7/8x + 3 = 15.75x = 12.75

13.

(x - 3)/21 = (x - 1)/279(x - 3) = 7(x - 1)9x - 27 = 7x - 79x - 7x = 27 - 72x = 20x = 10

14.

(2x + 5)/22 = (x + 10)/168(2x + 5) = 11(x + 10)16x + 40 = 11x + 11016x - 11x = 110 - 405x = 70x = 14

15.

(7x - 11)/(4x - 2) = 20/(35 - 20)(7x - 11)/(4x - 2) = 4/33(7x - 11) = 4(4x - 2)21x - 33 = 16x - 821x - 16x = 33 - 85x = 25x = 5

The answer to your question is b’(16,14)