A model rocket is launched upward with an initial velocity of 230 feet per second. The height, in feet, of the rockett seconds after the launch is given by h - -16+2300. How many seconds after the launch will the rocket be 330 feet above the ground? Round to the nearest tenth of a second.

it has changed from the width and the height.

step-by-step explanation:

geometry: triangles

solvers

lessons

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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