For what values of x and y are the triangles to
the right congruent by HL?

x = 6

y = 2

Step-by-step explanation:

For both triangles to be congruent, their hypotenuse lengths and the corresponding length of the other leg must be equal to each other.

Thus:

x = y + 4 ---› Eqn. 1

x + 2 = 4y › Eqn. 2

Substitute x = (y + 4) into equation 2.

(y + 4) + 2 = 4y

y + 4 + 2 = 4y

y + 6 = 4y

y - 4y = -6

-3y = -6

y = 2

Substitute y = 2 into equation 1

x = y + 4 ---› eqn. 1

x = 2 + 4

x = 6

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

it should be a.

hope it