How do you simplify this using the laws of exponents?

x1 = x61 = 6

x0 = 170 = 1

x-1 = 1/x4-1 = 1/4

xmxn = xm+nx2x3 = x2+3 = x5

xm/xn = xm-nx6/x2 = x6-2 = x4

(xm)n = xmn(x2)3 = x2×3 = x6

(xy)n = xnyn(xy)3 = x3y3

(x/y)n = xn/yn(x/y)2 = x2 / y2

x-n = 1/xnx-3 = 1/x3

Step-by-step explanation:

i hope this helps if its wrong just delete my answer

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

plz yuo

step-by-step explanation: