Mathematics, 27.01.2021 01:10 choudharykaran7997

The turtle and the hare are racing again! In the first 20 minutes of the race, the hare ran 19.5 meters and the turtle walked 5.89 meters. How much further did the hare run than the turtle? Use the algorithm to solve

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Answer from: brysong19

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GO TURTLE GO TURTLE GO TURTLE GO TURTLE

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GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

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GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE

GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE GO TURTLE

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Answer from: Quest

it should be a and d. lmk if i'm wrong xd

These dot plots show the ages (in years) for a sample of sea turtles and a sample of sharks.

Answer from: Quest

geometric series converge the common ratio r has magnitude less than one.

$|r| < 1$

which is equivalent to

$-1 < r < 1$

for the example we need

|2-x| < 1

-1 < 2-x and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1 diverges

1b. r=50/100=1/2 converges

when these converge they converge to

$s = \dfrac{a}{1 -r}$

where a is the first term.

$s = \dfrac{100}{1 - 1/2} = 200$

answer: 200

1c. r=-1 so it's not the case that |r| < 1. diverges

2a. x is the common ratio so we converge when |x|< 1

2b. r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c. r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

$|x| < \frac 1 2 \sqrt[3]{2}$

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The turtle and the hare are racing again! In the first 20 minutes of the race, the hare ran 19.5 met...

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