Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8? Quadratic formula: x =StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

1.39

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Given equation = 0=2x2+3x-8

Here, we use general formula of quadratic equation, then

By taking the value by given equation,

a = 2, b = 3, c= -8

by putting the value in equation , we get

x = [- 3 ± √3^2 - 4(2 × -8)] ÷ 2×2

= [- 3 ± √73] ÷ 4

= [- 3 ± 8.544] ÷ 4

So, for positive solution, we get

x = (-3 + 8.544) ÷ 4

x = 1.386 or 1.39

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.