The number of bagels and coffee sold by a bagel shop yesterday can be modeled using the equation b+c=84. Their sales for the same day can be modeled using the equation 2b+c=145. Solve this system of equations using substitution. How many bagels and coffee were sold

There were 61 bagels and 23 coffee sold

Step-by-step explanation:

Let us solve the question

∵ The number of bagels and coffee sold by a bagel shop yesterday

   can be modeled using the equation b + c = 84

∴ b + c = 84 ⇒ (1)

∵ Their sales for the same day can be modeled using the equation

   2b + c = 145

∴ 2b + c = 145 ⇒ (2)

Let us solve the system of equations using substitution

→ Subtract the two sides of equation (1) by b to find c in terms of b

∵ b - b + c = 84 - b

∴ c = 84 - b ⇒ (3)

→ Substitute c in equation (2) by equation (3)

∵ 2b + 84 - b = 145

→ Add the like terms on the left side

∴ (2b - b) + 84 = 145

∴ b + 84 = 145

→ Subtract 84 from both sides

∵ b + 84 - 84 = 145 - 84

∴ b = 61

→ Substitute the value of b in equation (3) to find c

∵ c = 84 - 61

∴ c = 23

∴ There were 61 bagels and 23 coffee sold.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.