Geometry CP Final Exam To show that AJKL = ALMJ by AAS, what must be the value of x?
(2x + 18)
К.
L
M м
(3x – 47)º
Choose...

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

ιт ωιℓℓ вєтнє fιяѕт ¢нσι¢є(α.)

convert the exponential equation to a logarithmic equation using the logarithm base (6) of the right side (36) equals the exponent (2).

ℓσg6(36)=2

нσρє ι ¢συℓ∂ нєℓρ уα