Three of the vertices of square ABCD are located at A(0,3), B(4,0), and C(7,4). Determine the area of square ABCD.

The area of the square ABCD is 25 square units

Step-by-step explanation:

The square ABCD has three of its vertices at A(0,3), B(4,0), and C(7,4). The fourth vertex has been also plotted in the image attached below.

The area of the square is

Where a is the length of any of the square's sides. We only have to find the distance from any two consecutive vertices, for example, A(0,3), B(4,0):

a = 5

Calculating the distance between any other pair of consecutive vertices would yield the same result. The area is now calculated:

The area of the square ABCD is 25 square units

191 students play sports and ninety-seven 10th graders were surveyed.

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !