How much energy is absorbed by 250.0 g of water when its temperature rises from 25.0 ºC to 88.5 ºC? Specific heat capacity of water is 4.184 J/gºC.

.

(4.18 J/g°C) x (100.0 mL x 1.000 g/mL) x (37 - 4.0)°C = 13794 J = 13 kJ

2.  

(455 J) / (25.0 g) / (155 - 25)°C = 0.140 J/g°C

3.  

(4.184 J/g°C) x (20.0 g) x (303.0 - 283.0)°C = 1674 J

5.  

(0.129 J/g °C) x (85.0 g) x (200.0 - 10.0)°C = 2083 J

Step-by-step explanation:

I think this is the right answer, I am very, very sorry if I'm wrong

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i need the table so i can see

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct