What is an equation of the line that passes through the points (4,1) and (8, -3)? Put your answer in fully reduced form.

y=-x+5

Step-by-step explanation:

first, let's find the slope of the line (m), using the equation (y2-y1)/(x2-x1)

here are the given points: (4,1) and (8,-3)

label the points:

x1=4

y1=1

x2=8

y2=-3

now substitute into the equation

m=(-3-1)/(8-4)

m=(-4)/4

m=-1

the slope of the line is -1.

Now, use slope-point form, which is y-y1=m(x-x1)

substitute the numbers into the equation

y-1=-1(x-4)

do distributive prop

y-1=-x+4

add 1 to both sides

y=-x+5

the equation of the line is y=-x+5

hope this helps :)

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2