The failure of a circuit board interrupts work that utilizes a computing system, until a new board is delivered. The delivery time, Y, is uniformly distributed on the interval two to six days. The cost of a board failure and interruption includes the fixed cost c0 of a new board and a cost that increases proportionally to Y2. If C is the cost incurred, C = c0 + c1Y2. A) Find the probability that the delivery time exceeds two days.
B) In terms of c0 and c1, find the expected cost associated with a single failed circuit board.

a) 1  ( 100% )

b)   Co + 46/3 C1

Step-by-step explanation:

Delivery time = Y

Interval = 2 to 6 days

cost incurred ( C ) = Co + C1 Y^2

a) determine the probability that the delivery time exceeds two days

since the delivery time is uniformly distributed on the interval 2 to 6 days the probability of having a delivery time > 2 days will be = 1

b) Determine the expected cost associated with a single failed circuit board

E ( Y^2 ) = 46/3

hence the cost associated with a single failed circuit board =

E ( C ) = Co + 46/3 C1

attached below is a detailed solution

∡ eia and ∡ kij are congruent

step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!