c.) The sonar of a navy cruiser detects a submarine that is 4000 feet from the cruiser. The angle between the water line and the submarine is 34° How deep is the submarine?

2236.77 feets

Step-by-step explanation:

From the attached picture, we are to find x, which is the vertical depth of the submarine.

Using trigonometry based on the illustration in the diagram:

Sinθ = opposite / hypotenus

Sinθ = x (depth of submarine) / distance from ship (4000)

Hence,

Sinθ = x / 4000

θ = 34°

Sin34 = x / 4000

0.5591929 * 4000 = x

2236.7716 = x

Hence, depth of submarine = 2236.77 feets

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

i think asking google will you get the answer to that question