2. There are 12 girls and 3 boys in a group of children. One child was chosen at random from the group. Another child was chosen at random from the remaining children. What is the probability that
a. The first child chosen was a girl
b. The first child chosen was a girl and the second was a boy
C. A child of each sex was chosen

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: 5100 just subtract

step-by-step explanation:

0.038

step-by-step explanation: