Write the equation of the line in slope-intercept form.
perpendicular to y= 2x+6 and
passing through (-4,2)

Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2

slope of the req. line = -1/2

equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y  = (-1/2)x

this is your req. equation of line.

Do you have answer choices?