Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use?

Options :

Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.

Determine whether the equation has the form x = a

Step-by-step explanation:

Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3

-3(x + 1) + 3x = - 3(x - 1) + 3

If the equation has the form x =a, where a is the unknown and a is the value of the unknown 'x'

Expanding :

-3x - 3 + 3x = - 3x + 3 + 3

-3x + 3x -3 = - 3x + 6

-3 = - 3x + 6

-3 - 6 = - 3x

-9 = - 3x

x = 9/3

x = 3

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!

c-   36

taxicab circle radius 9 has 4(9) = 36 points