Police chases a driver. The police is 1 mile behind the driver. The speed of the police is 90 mph, and the speed of the chased car is 85 mph. How long will it take for the police to catch up with the car?

0.20 hour

Step-by-step explanation:

According to the problem, computation of the given data are as follows,

Speed of police = 90 mph

Speed of chased car = 85 mph

Distance to be chased = 1 mile

So, we can calculate the time to catch by using following formula:

Time required = Distance between two cars ÷ (Speed of Car A - Speed of Car B)

= 1 ÷ ( 90 - 85)

= 1 ÷ 5

= 0.20 hour

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.