Every morning, siblings Jack and Jill roll a regular six-sided die to determine who will get to ride in the front seat on the way to school. If the number is even, Jack gets to ride in the front. If the number is odd, Jill gets to ride in the front. A. In the first 20 school days, how many times would you expect Jack to get to ride in the front seat? B. In the first 100 school days, how many times would you expect Jill to get to ride in the front seat? C. Which prediction (Jack or Jill's) do you think will be closer to the actual frequency? Use complete sentences to justify your answer.

Answer and explanation:

Probability= number of favorable outcomes/total number of outcomes

A regular six-sided die which is numbered from 1 to 6 has 3 even numbers(2,4,6) and 3 odd numbers(1,3,5)

A. Given that Jack will only ride in the front seat if the number is even, probability that Jack would ride in the front seat = 3/6=1/2

Therefore Jack will ride in the front seat half the time. In 20 days, Jack would ride in the front seat for 10 days.

B Given that Jill will ride in the front seat if the number is odd, probability that he would ride in the front seat = 3/6=1/2

Or we could simply say probability that Jill will ride in the front seat given that probability that Jack will ride in the front is 1/2 =1-1/2=1/2

C. Both predictions are likely to be closer to the actual frequency based on probability calculated.

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: