Find the value of x...

10x+41=[5+-7]+[2x-2]

we move all terms to left 10x+41-[[5x-7+[2x-2]]=0

Step-by-step explanation:

l calculate terms in parentheses

5x+2x-7-2

we add all the numbers together, and 7x-9 back to the equation -7x-9]

we get ride of parentheses 10x-7+9+41=0 we add all the numbers together,and all 3x+50=0

we move all the terms containg x to the left, all other therms to the right 3x=50

x=-50\3

x-50\3

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)