A chemist has a mixture with a temperature of 3.5°C. Then the chemist cools the mixture. The temperature changes by -14.2°C. What is the temperature of the mixture after it cools? Show your work.

-10.7°C

Step-by-step explanation:

The change in the temperature is the difference between the initial  temperature and the final temperature. Let the initial temperature be T1 and the final be T2 then the change in temperature will be

= T2 - T1

Hence

-14.2 = T2 - 3.5

T2 = -14.2 + 3.5

= - 10.7°C

The temperature of the mixture after it cools is -10.7°C

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

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