Isabelle has $5.45 in her purse. If she has five more nickels than dimes, and twice as many quarters than dimes, how many of each type of coin does she have?

Nickel = 13

Dimes = 8

Quarters = 16

Step-by-step explanation:

Let N denote Nickel,

Let D denote dime

Let Q denote quarter

Now, from online conversions;

1 nickel = 5 cents

Also, 1 dime = 10 cents

Also, 1 quarter = 25 cents

Isabelle has $5.45 which is also 545 cents.

Thus, we have;

5N + 10D + 25Q = 545 - - - (eq 1)

We are told that;

she has five more nickels than dimes, and twice as many quarters than dimes.

Thus;

N = D + 5

Also, Q = 2D

Plugging them for N and Q in eq 1 givens;

5(D +5) + 10D + 25(2D) = 545

5D + 25 + 10D + 50D = 545

25 + 65D = 545

65D = 545 - 25

65D = 520

D = 520/65

D = 8

Thus; N = D + 5 = 8 + 5 = 13

Q = 2D = 2 × 8 = 16

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

two data sets with the same median will not have the same varaibility

step-by-step explanation: