A cashier will randomly choose two coins one at a time without replacement. What is the probabilty that the cashier will chose a penny first, followed by a dime?

Complete question is;

A cash register contains coins. 10 pennies, 11 nickels, 13 dimes, and 6 quarters. A cashier will randomly choose two coins one at a time without replacement. What is the probability that the cashier will choose a penny first, followed by a dime?

1/12

Step-by-step explanation:

We are told there are 10 pennies, 11 nickels, 13 dimes, and 6 quarters.

Thus total number of coins = 10 + 11 + 13 + 6 = 40 coins

Probability of picking a penny first is;

10/40 = 1/4

After which we will have 39 coins left.

Probability of a dime after that will be 13/39 = 1/3

Thus,probability of picking a penny first then a dime will be; ¼ × ⅓ = 1/12

46 dollars is the answer.

step-by-step explanation:

6*6 = 36,         36+10=46

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step-by-step explanation: