Mathematics, 15.10.2019 03:40 dominikbatt

Sin^2x-cos^2x=0
solve for the equation for the interval [0, 2pi)

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Sin^2x-cos^2x=0
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Sin^2x-cos^2x=0 solve for the equation for the interval [0, 2pi)

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Another question on Mathematics

Sin^2x-cos^2x=0
solve for the equation for the interval [0, 2pi)