10.ABCD is a rhombus such that measure of angle ACB is 40º find the measure of angle ADC.

ADC = 100 degrees

Step-by-step explanation:

Please check attachment for diagrammatic representation of the Rhombus

From what we can see in the diagram;

angle CBD and CDB are equal

The reason for this is that we have an isosceles in triangle CBD

CBD = 90- ACB

CBD = 90-40 = 50

We need ADB to completely calculate ADC

CAB is also 40 from the isosceles ABC

That means DBA = 90 - CAB = 90-40 = 50

So from isosceles ABD, we have that ADB is also 50

Mathematically;

ADC = ADB + DBA

ADC = 50 + 50

ADC = 100

5

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.