Can someone please do the 2a 2b 2c 2d 2e and 2f ill mark u brainlist

2a: 5

2b: 7

2c: 10

2d: 2

2e: 3

2f: 2

Step-by-step explanation:

To solve all of these you just get the variable (x) by itself

2A: 9x-41=39-7x

Add 7x from both sides and then add 41 to get

16x=80

Divide by 16 and get x=5

2B: 3x-13=50-6x It's the same process as before for this question

Add 6x and 13 to both sides to get

9x=63

divide by 9 and get x=7

2C: 5x-17=83-5x

Add 5x and 17 to both sides

10x=100

divide by 10

x=10

2d: 13x-16=24-7x

Add 7x and 16 to both sides to get

20x=40

divide by 20 and get x=2

2e: 12x-13=53-10x

Add 10x and 13 to both sides to get

22x=66

divide by 22 and get x=3

2f: 17x-21=51-19x

Add 19x and 21 to both sides and get

36x=72

divide by 36 and get x=2

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.