Really urgent Bus X, Bus Y and Bus Z leave the bus terminal every 35 minutes, 40 minutes and 42 minutes respectively. Given that the 3 buses leave the interchange together at 0620, what would be the next time the three buses leave together?

Step-by-step explanation:

Find the lowest common multiple between the numbers

35 = 5×7

40 = 2³×5

42 = 2×3×7

So the lowest common multiple is:

2³×3×5×7 =840 minutes

840 minutes is 14 hours so the next time they are all at the interchange is 2020 hours.

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step-by-step explanation:

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isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c