GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the outside of the garden. The area of the garden and the walkway together are 396 square feet. What is the width of the walkway? I will give you a hint on how to start:

The new width is 10 + 2x and the new length is 14 + 2x.

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area of garden and the walkway together is

Divide both sides by 4.

Splitting the middle term, we get

Using zero product property, we get

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer: i guess 5 units?

step-by-step explanation: