What are the vertex and axis of symmetry of the parabola y = x2 – 16x + 63? A.
vertex: (8, -1); axis of symmetry: x = 8

B.
vertex: (8, 1); axis of symmetry: x = 8

C.
vertex: (-8, 1); axis of symmetry: x = -8

D.
vertex: (-8, -1); axis of symmetry: x = -8

A

Step-by-step explanation:

Remember that the x-value of the vertex when an equation is given in standard form can be found with the equation . So, we can take the coefficients from the equation and plug them in.

Now we know that the x-value of the vertex is 8. Next, the equation for the y-value is , where h is the x-value of the vertex (8).

So the vertex is (8,-1).

Finally, the axis of symmetry is the x-value of the vertex, also called h.

Final answer, vertex: (8,-1) and axis of symmetry: x=8

Hope this helps!

a. is correct

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.