Which point is located on the line represented by the equation y+4=-5(x-3)?

The answer would be (3,-4) This is because if you replace the variables with the numbers and solve the equation it will come out 0=0

So, lets solve.

y+4=-5(x-3)

-4+4=-5(3-3)

0=-5x0

0=0

So therefore the correct answer will be (3,-4)

Hope this helped

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204