An observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from his line of sight. How high is the kite flying over the building? You must show all work and calculations to receive full credit. (10 points) A right triangle is shown with one leg measuring 400 and another leg measuring h with an angle across from it measuring 29 degrees

h ≈ 221.7236 ft

Step-by-step explanation:

The illustration above forms a right angle triangle. The right-angle triangle formed has an adjacent side of 400 ft which is the distance of the observer from the building. The opposite side of the triangle is the height of the kite flying over the building which is represented as h. The angle of elevation from the observer line of sight is 29°.

Using tangential ratio

tan 29° = opposite/adjacent

tan 29° = h/400

cross multiply

h = 400 tan 29°

h = 400 × 0.55430905145

h = 221.723620581

h ≈ 221.7236 ft

the correct answer is x/3+10≥32

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