Write the equation of the line, in slope-intercept form, that has a slope of -8/5and contains the point

y = -8/5x + 23/5

Step-by-step explanation:

Complete question

Write the equation of the line, in slope-intercept form, that has a slope of -8/5and contains the point (6, –5)

The equation of a line in pint slope form is expressed as;

y - y0 = m(x-x0)

Given

m = -8/5

(x0, y0) = (6, -5)

Substitute into the formula

y - (-5) = -8/5(x-6)

y+5 = -8/5(x-6)

Multiply through by 5

5(y+5) = -8(x-6)

5y + 25 = -8x + 48

5y = -8x +48 - 25

5y = -8x + 23

y = -8/5x + 23/5

Hence the equation in slope intercept form is y = -8/5x + 23/5

step-by-step explanation:

this woman was an important writer and propagandist during the american revolution. she was a member of the committee of correspondence (in fact the committee was formed in her home) and was an advisor to many of the revolutionary leaders, including george washington and john adams. who was this revolutionary woman?