HELP When Jackson moved into a new house, he planted two trees in his backyard. At the time of planting, Tree A was 24 inches tall and Tree B was 36 inches tall. Each year thereafter, Tree A grew by 10 inches per year and Tree B grew by 7 inches per year. Let A represent the height of Tree A t years after being planted and let B represent the height of Tree B t years after being planted. Write an equation for each situation, in terms of t, and determine the height of both trees at the time when they have an equal height.

For tree A: 24+10t

For tree B: 36+7t

They are at the same height at 4 years at a height of 64 inches

Step-by-step explanation:

To figure out when the trees are at the same height make the equations equal to each other and solve for T

24+10t=36+7t

Subtract 24 and 7t from both sides to get

3t=12

divide by 3 to get

t=4

This means at t=4 they are at equal height so we plug this into any of the equations

24+10*4

this is equal to 64

We can double check by plugging t=4 into the second equation

36+7*4

36+28=64

a

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2