The spinner has 5 congruent sections. Which list contains all possible outcomes after the spinner is spun 2 times?

(2, 2), (4, 4), (6, 6), (8, 8), (10, 10)
(2, 2), (4, 4), (6, 6), (8, 8), (10, 10)

(2, 2), (2, 4), (2, 6), (2, 8), (2, 10),
(4, 2), (4, 4), (4, 6), (4, 8), (4, 10),
(6, 2), (6, 4), (6, 6), (6, 8), (6, 10),
(8, 2), (8, 4), (8, 6), (8, 8), (8, 10),
(10, 2), (10, 4), (10, 6), (10, 8), (10, 10)
(2, 2), (2, 4), (2, 6), (2, 8), (2, 10), (4, 2), (4, 4), (4, 6), (4, 8), (4, 10), (6, 2), (6, 4), (6, 6), (6, 8), (6, 10), (8, 2), (8, 4), (8, 6), (8, 8), (8, 10), (10, 2), (10, 4), (10, 6), (10, 8), (10, 10)

(2, 2), (2, 4), (2, 6), (2, 8), (2, 10),
(4, 4), (4, 6), (4, 8), (4, 10),
(6, 6), (6, 8), (6, 10),
(8, 8), (8, 10),
(10, 10)
(2, 2), (2, 4), (2, 6), (2, 8), (2, 10), (4, 4), (4, 6), (4, 8), (4, 10), (6, 6), (6, 8), (6, 10), (8, 8), (8, 10), (10, 10)

(2, 4), (2, 6), (2, 8), (2, 10),
(4, 2), (4, 6), (4, 8), (4, 10),
(6, 2), (6, 4), (6, 8), (6, 10),
(8, 2), (8, 4), (8, 6), (8, 10),
(10, 2), (10, 4), (10, 6), (10, 8)

answer

point o.

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.