Can someone please help me??

b=3, y=6

Step-by-step explanation:

Label the 2 equations:

2b +6y= 42 (1)

2b +4y= 30 (2)

(1) -(2):

(2b +6y) -(2b +4y)= 42 -30

2b +6y -2b -4y= 12

2y= 12

y= 12 ÷2 (÷2 on both sides)

y= 6

Susbt. y=6 into (2):

2b +4(6)= 30

2b +24=30

2b= 30 -24 (-24 on both sides)

2b= 6

b= 6 ÷2

b= 3

y = 6, b = 3

Step-by-step explanation:

Since both equations have 2b in them, subtracting them gets you a quick result because the 2b-2b cancels out!

2b + 6y = 42

2b + 4y = 30

-

       2y = 12

         y = 6

Then 2b = 42 - 36 = 6, so b = 6/2 = 3

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse