A particle traveled a distance of 9.0×10^12 meters at a rate of 1.8×10^5 meters per second. If distance = rate x time, how many seconds did it take the particle to travel the specified distance?

2x3 – 6x2 – 14x + 24 square centimeters

if i'm wrong i'm sorry : )

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value