Quickkk please help and how all work

x=3y-1
3x+4y=10

y=1, x=2

Step-by-step explanation:

so first solve for y. plus x=3y-1 into the other equation.  

so 3(3y-1)+4y=10.  

Simplify

9y-3+4y=10           Add 3 to both sides

9y+4y=13               Add

13y=13 .                  Divide 13 from both sides

y=1

Plug 1 into the first equation.  

x=3(1)-1

x=3-1

x=2 and y=1

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

step-by-step explanation: