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Mathematics, 21.01.2021 21:00 maribelmartine8919

Solve the following equation algebraically: Negative 16 = 16 x squared
How many solutions does this equation have? Explain.
a.
Negative 1 = x squared; One solution because only -1 will satisfy the equation.
b.
Negative 1 = x squared; No real solution because there is no real number that, when squared, produces -1.
c.
1 = x squared; Two solutions because the square root of 1 is positive 1 and negative 1.
d.
1 = negative x squared; One solution because only -1 will satisfy the equation.

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Solve the following equation algebraically: Negative 16 = 16 x squared
How many solutions doe...
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